1  void foo (int n, double a, double *b, double *x)
       2  {
       3    int i, j;
       4  
       5    if(n <= 0) return;
       6    if (a == 0.0e0) return;
       7  
       8    if (a > 5.0)
       9      {
      10        i = 0;
      11        goto sec;
      12      }
      13    for (i = 0; i < 1024; i++)
      14      {
      15        double y = b[i];
      16  sec:
      17        b[i+1] = y + 5.0;
      18        for (j = 0; j < n; j++)
      19  	x[j] = x[j] + a;
      20      }
      21  }