python (3.12.0)
1 """
2 Broken bytecode objects can easily crash the interpreter.
3
4 This is not going to be fixed. It is generally agreed that there is no
5 point in writing a bytecode verifier and putting it in CPython just for
6 this. Moreover, a verifier is bound to accept only a subset of all safe
7 bytecodes, so it could lead to unnecessary breakage.
8
9 For security purposes, "restricted" interpreters are not going to let
10 the user build or load random bytecodes anyway. Otherwise, this is a
11 "won't fix" case.
12
13 """
14
15 import types
16
17 co = types.CodeType(0, 0, 0, 0, 0, 0, b'\x04\x00\x71\x00',
18 (), (), (), '', '', 1, b'')
19 exec(co)
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